No. 3 Ohio State will play No. 2 Clemson in the Fiesta Bowl

COLUMBUS (AP/NBC4) — The No. 2 Ohio State Buckeyes will play No. 2 Clemson in the Fiesta Bowl on December 31, it was announced today.

The Buckeyes and Tigers face off at the University of Phoenix Stadium in Glendale at 7 p.m. EST.

No. 1 Alabama will play No. 4 Washington in the Peach Bowl that same day.

Penn State comes in at No. 5 and Michigan at No. 6 in the final CFP rankings.

The Crimson Tide was No. 1 in the final AP Top 25 of the regular season Sunday, just as it has been since the preseason. Ohio State is No. 2, Clemson is No. 3 and Washington is No. 4. The Super 16 poll puts Alabama at No. 1, Clemson at No. 2. Washington and Penn State round out the top five in the Super 16 at No. 4 and 5, respectively.

Penn State was fifth, followed by Michigan, Oklahoma and Wisconsin.

The Crimson Tide enters the postseason looking to win back-to-back championships and to join Florida State in 1999 and Southern California in 2004 as the only teams to be AP No. 1 from start to finish.

Alabama would be the 12th team to win two straight AP championships.

In the National Football Foundation Super 16 poll, Ohio State comes in at No. 3 provides commenting to allow for constructive discussion on the stories we cover. In order to comment here, you acknowledge you have read and agreed to our Terms of Service. Commenters who violate these terms, including use of vulgar language or racial slurs, will be banned. Please be respectful of the opinions of others and keep the conversation on topic and civil. If you see an inappropriate comment, please flag it for our moderators to review.

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